Answer:
![\sqrt[5]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B4%7D)
+ ![\sqrt[10]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7B3%7D)
Step-by-step explanation:
We sure can write 2^2/5+ 3^1/10 as 
// use the ![a^{\frac{m}{n} } =\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
to transform the expression
Convert 
to ![\sqrt[5]{2^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E%7B2%7D%20%7D)
= (here a = 2, n = 5, m = 2)
Then convert 
to ![\sqrt[10]{3^{1} }](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7B3%5E%7B1%7D%20%7D)
= (here a = 3, n = 10, m = 1)
Now we get = + . This is the simplified form, which is the answer.
Answer:
x > -1
Step-by-step explanation:
Simplify both sides of the equation, then isolate the variable.
10 y plus 9 y minus 6 y plus 6 y
=> 10y + 9y - 6y + 6y
= 10y + 9y - 0 = 19y
9514 1404 393
Answer:
C)
Step-by-step explanation:
The table that has a constant ratio between y and x values is the one that represents a proportional relationship.
A) 2/4 ≠ 4/16
B) 1/1 ≠ 4/16
C) 6/8 = 12/16 = 18/24 = 30/40, a proportional relationship
