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3 years ago

How would you write an equation with a slope of 2/3 and a y-intercept of -3

Mathematics

2 answers:

Naddik [55]3 years ago

6 0

Answer:

Step-by-step explanation:

so obviously your slop is 2/3. so it starts with y=2/3. so B is out of the question. since the slope is x in the equation, you still have to add the x in the equation; y=2/3x

dimaraw [331]3 years ago

5 0

Answer: The answer is C) y= 2/3x-3

Step-by-step explanation:

i figure it out

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Can you help me with this question please

solniwko [45]

Answer:

the answer is 9^8

Step-by-step explanation:

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3 years ago

Read 2 more answers

Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

Can you guy's please help me out I was absent and now I don't have a clue!

Elena-2011 [213]

For these problems you have to use PEMDAS so for problem 15 you would do the parentheses first, (21-3) you get 18 and then exponents, 3^2, you get 9, no multiplication but there is division so take your answers, 18 and 9 and divide them, you get 2, so the answer to 15 is 2.

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3 years ago

Find the missing side of the triangle

Yuri [45]

Answer:

x = 15

Step-by-step explanation:

Pytago: a^2 + b^2 = c^2

x = $\sqrt{25^{2} -20^{2} }$ = 15

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2 years ago