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Marina CMI [18]
3 years ago
8

8. A right cone has a volume of 8,579 m3 and a radius of 16 m. Find its altitude.

Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:

Option A is correct.

Step-by-step explanation:

The formula used for finding the volume of right cone is:

Volume of Right cone = (1/3)π.r².h

We need to find altitude i.e h

Volume of cone=V = 8579 m^3

Radius=r = 16m

Altitude =h =?

Putting values,

8579 = (1/3) * 3.14 * (16)^2*h

8579 = 1/3 * 3.14 * 256 *h

8579 = 267.95 * h

=> h = 8579/267.95

h = 32.0 m

So, Altitude of right cone is 32.0 m

Option A is correct.

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Answer:

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Step-by-step explanation:

6(2 − 6x) ≤ 4 − 35x

Expand bracket;

12 - 36x ≤ 4 − 35x

Add 36x to both sides to get;

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Subtract 4 from both sides to get;

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Answer:

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Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

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The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

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Explanation:

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