Question

Simplify open parentheses x to the 4 fifths power close parentheses to the 3 sevenths power.

Answer 1

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Answer 2

Answer:

$x^\frac{12}{35}$

Step-by-step explanation:

Here let us first write our expression

It says, x raise to 4 5th power i.e 4 by 5 , again raise to 3 7th power i.e 3 by 7

or $(x^{\frac{4}{5}})^\frac{3}{7}$

Now in this we apply the rule of product of exponents . The rule is like this.

$(x^{m})^{n}=x^{mn}$

Let us apply the rule in our problem

$(x^{\frac{4}{5}})^\frac{3}{7} = x^{\frac{4}{5}*\frac{3}{7}}$

$x^{\frac{4}{5}*\frac{3}{7}} = x^{\frac{4*3}{5*7}}$

$x^{\frac{4*3}{5*7}}=x^{\frac{12}{35}}$

Which is x to the 12 over 35 hence our b option is correct