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Elodia [21]
3 years ago
11

Help me solve this please

Mathematics
1 answer:
vitfil [10]3 years ago
7 0

Answer:

angle P congruent to angle N

Step-by-step explanation:

You know the angles at Q are congruent.

If angle P is congruent to angle N, then angle R is congruent to angle D.

Then both triangles are similar.

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Given the functions =−12 (2)x+3. Select all statements that are true.
Natali5045456 [20]
There ya go, the graphing

8 0
2 years ago
What is the measurement of N?<br> A) 45° <br> B) 90° <br> C) 100° <br> D) 180°
puteri [66]
N would equal 45° since the tiny square means its 90°. 90-45=45.
5 0
3 years ago
Read 2 more answers
If m∠NOP = 24 and m∠NOQ = 110, what is m∠POQ? Angle N O Q divided into two unequal angles by ray O P. A. 62 B. 86 C. 134 D. 156
Dmitrij [34]

Answer:

<em>B. 86 degrees</em>

Step-by-step explanation:

Given the following angles:

m∠NOQ = 110

m∠NOP = 24

Using the addition postulate:

m∠NOQ =  m∠NOP + m∠POQ

110 = 24 + m∠POQ

m∠POQ = 110 - 24

m∠POQ = 86

<em>Hence the measure of m∠POQ is 86 degrees</em>

5 0
2 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
2 years ago
Find the inequality represented by the graph.
iris [78.8K]

Answer:

<h2>x \geqslant  \frac{y + 4}{3}</h2>

Explanation;

Associated line with this equation is:

y=mx+c

when,

X=0

y=-4

so, c=-4

X=1

y=-1

- 1 = m- 4 \\  - m =  - 4 + 1 \\  - m =  - 3 \\ m =3 \\

y = 3x - 4 \\ or \: y + 4 = 3x \\ or \:  \frac{y + 4}{3}  = x

Inequality representated by graph:

x \geqslant  \frac{y + 4}{3}

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
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