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3 years ago

Question Translate and solve: What number is 132% of 694? Round to the nearest hundredth.

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

8 0

Answer:

916.08

Step-by-step explanation:

132% *694 =

(132*694)/100 =

91608/100 = 916.08

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Margarita [4]

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3 years ago

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Andrews [41]

Answer:

Step-by-step explanation:

Given

3 $(x+9)^{\frac{3}{4} }$ = 24 ( divide both sides by 3 )

$(x+9)^{\frac{3}{4} }$ = 8

Raise both sides to the power of $\frac{4}{3}$

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3 years ago

The position of an object moving along a straight line for

NikAS [45]

Answer:

at 2/3 seconds

Step-by-step explanation:

S1(t) = t³ + 2

Average speed, dS1/dt = 3t²

S2(t) = t²

Average speed, dS2/dt = 2t

The distance between the objects is

dS1/dt - dS2/dt

= 3t² - 2t

The time the distance between the two object is at minimum is when the distance is 0

That is, when

3t² - 2t = 0

t(3t - 2) = 0

t = 0 or 3t - 2 = 0

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3 years ago

A frame is 6in tall and 8 in wide. What if it was reduced to a width of 4in then how tall will it be

kkurt [141]

Answer:

3 in

Step-by-step explanation:

Apparently, we are to assume that the height and width are proportional:

height/width = (6 in)/(8 in) = (new height)/(4 in)

Multiplying by 4 in will tell us the new height:

new height = (4 in)(6/8) = 3 in

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3 years ago

In a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer

stira [4]

Answer:

We conclude that 80% of patients stop smoking when given sustained care.

Step-by-step explanation:

We are given that in a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer smoking after one month.

Let p = percentage of patients stop smoking when given sustained care.

So, Null Hypothesis, $H_0$ : p = 80% {means that 80% of patients stop smoking when given sustained care}

Alternate Hypothesis, $H_A$ : p $\neq$ 80% {means that different from 80% of patients stop smoking when given sustained care}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of patients who stop smoking when given sustained care = 80.2%

n = sample of patients = 192

So, the test statistics = $\frac{0.802-0.80}{\sqrt{\frac{0.802(1-0.802)}{192} } }$

= 0.07

The value of z test statistics is 0.07.

Also, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.07) = 1 - P(Z $\leq$ 0.07)

= 1 - 0.52790 = 0.4721

Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 80% of patients stop smoking when given sustained care.

8 0

3 years ago