1)a^7/a^4
=a^[7-4]
=a³
2) r²s⁴t/r²st³
=s⁴-¹.t¹-³
=s³.t-²
=s³/t²
3)3x^6/18x
=x^5/6
We can set up 2 equations given the information.
Let the price of advance ticket be represented by A and same day ticket by S
A + S = 50
20A + 40S = 1700
Solve for A in the first equation by subtracting S on both sides.
U will get A = 50 - S
Now substitute 50 - S for A in the second equation.
20 (50 - S) + 40S = 1700
1000 - 20S + 40S = 1700
20S = 700
S = 35
Same day ticket costs $35 and advance ticket costs $15
The answer is: A - f(x) = 1/2 cos (x)
Multiply -12 to each of the terms (make sure to carry the negative!)
-36a - 24b + 12 will be your final answer :)
