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Shtirlitz [24]
3 years ago
9

All solutions are _____.

Chemistry
2 answers:
Afina-wow [57]3 years ago
6 0
Homogeneous mixtures will be your answer
hope this helps!
Flauer [41]3 years ago
4 0

Answer : The correct option is, homogeneous mixtures

Explanation :

True solution : It is a homogeneous mixture in which the two or more substance is dissolved in the solution. The particle size is between 0.1 nm to 1 nm, then the solution is considered as a true solution.

Colloid : It is solution in which the one substance is insoluble in another solution that means the insoluble substance rotating in the solution. The particle size is between 2 to 1000 nm, then the solution is considered as a colloid.

Suspension : It is solution in which the one substance is insoluble in another solution that means the insoluble substance is sedimented into the solution. It is a heterogeneous mixture. The particle size is greater than 1000 nm, then the solution is considered as a suspension.

Heterogeneous mixtures  : It is a mixture that appears non-uniformly throughout the solution and the particle size or shapes are also different.

Homogeneous mixtures  : It is a mixture that appears uniformly throughout the solution and the particle size or shapes are not different.

Hence, all solutions are homogeneous mixtures.

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How many grams of Br are in 335g of CaBr2
ASHA 777 [7]
The answer is 267.93 g

Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol

The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%

Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
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