All categories

3 years ago

Please help in test first to answer will get BRAINLIEST

Chemistry

2 answers:

Sophie [7]3 years ago

7 0

Answer:

C. Arch

Explanation:

Hope the helps

RSB [31]3 years ago

4 0

Answer:

Arch

Explanation:

Please mark me brainliest and thank and rate 5 stars.

You might be interested in

Choose the correct answer to complete the paragraph about the acceptance of the heliocentric model. In the second century BCE, t

PtichkaEL [24]

Answer:epicycles,copermicus, earth

Explanation:

4 0

3 years ago

Read 2 more answers

An ideal gas fills a balloon at a temperature of 227ºC and standard pressure. By what factor will the volume of the balloon chan

Vladimir [108]

Answer:

e. 327/227

Explanation:

This is the correct standard pressure.

5 0

2 years ago

Check out the list of scientific names. These names all represent animals. These are all animals but they cannot reproduce to pr

Dimas [21]

Answer:

Explanation:

they are not the same animal

7 0

2 years ago

A sheet of polyethylene 1.5-mm thick is being used as an oxygen barrier at a temperature of 600K. If the flux is 2.48 x 10-5 kg/

Eddi Din [679]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of high-pressure side is $C_1 = 0.722 \ kg/m^3$

Explanation:

From the question we are told that

The thickness of the polyethylene is $d = 1.5 \ mm = 0.0015 \ m$

The temperature is $T = 600 \ K$

The flux is $JA = 2.48 *10^{-5} \ kg/m^2\cdot s$

The concentration on the low-pressure side is $C_2 = 0.5 \ kg/m^3$

The initial diffusivity is $D_o = 6.2 *10^{-4} \ m^2 /s$

The activation energy for diffusion is $Q_d = 41 \ kJ /mol = 41*10^3 J /mol$

Generally the diffusivity of the oxygen at 600 K can be mathematically evaluated as

$D = D_o * e^{- \frac{Q_d}{R * T } }$

substituting values

$D = 6.2*10^{-4} * e^{- \frac{41 *10^3}{8.314 * 600 } }$

$D = 1.671 *10^{-7} \ m^2 /s$

Generally the flux is mathematically represented as

$JA = D * \frac{C_1 -C_2}{d}$

Where $C_1$ is the concentration of oxygen at the higher side

$C_1 = d * \frac{JA}{D} + C_2$

substituting values

$C_1 = 0.0015 * \frac{2.48*10^{-5}}{1.671*10^{-7}} + 0.5$

$C_1 = 0.722 \ kg/m^3$

6 0

3 years ago

A given volume of methane diffuses in 20 seconds. How long will it take the same volume of hydrogen to diffuse under the same co

Airida [17]

The time taken for the same volume of methane gas to diffuse is 7.1 s.

<h3>Rate of gas diffusion</h3>

The rate at which a given mass of diffuses is inversely proportional to the molar mass of the gas.

$\frac{t_2}{t_1} = \sqrt{\frac{M_2}{M_1} }$

where;

M1 is the molar mass of methane (CH4) = 16 g
M2 is the molar mass of hydrogen as = 2
t1 is time taken for methane = 20 s
t2 is the time taken for hydrogen = ?

$\frac{t_2}{t_1} = \sqrt{\frac{M_2}{M_1} }\\\\\frac{t_2}{20} = \sqrt{\frac{2}{16} }\\\\\frac{t_2}{20} = \frac{\sqrt{2} }{4} \\\\t_2 = \frac{20\sqrt{2} }{4} \\\\t_2 = 5\sqrt{2} \\\\t_2 = 7.1 \ s$

Thus, the time taken for the same volume of methane gas to diffuse is 7.1 s.

Learn more about rate of gas diffusion here: brainly.com/question/26696466

6 0

2 years ago

Read 2 more answers