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3 years ago

Select the reagents you would use to synthesize the compounds below from benzene. Use the minimum number of steps.

Chemistry

1 answer:

iris [78.8K]3 years ago

5 0

Answer:

Explanation:

For the reaction of m-bromonitrobenzene from benzene first, we need to carry out the nitration of benzene utilizing HNO3, H2SO4.

Bromination of nitrobenzene with Br2, FeBr3 outfits m-bromonitrobenzene in light of the fact that nitro group is meta coordinating for electrophile. The mechanism activity for the reaction is shown in the image below.

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How many grams are in 0.39 moles of water

Shtirlitz [24]

Answer: 7.025959200000001

Explanation:

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2 years ago

Which of the following is the main function of the Circulatory System?

kolbaska11 [484]

Answer:

B: The transport oxygen and nutrients around your body and help to get rid of wastes

Explanation:

The circulatory system carries oxygen and nutrients to the body, but it can also help get rid of waste (though that isn't a huge function of it).

8 0

3 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

Woodpeckers find insects to eat by pecking holes in trees with their beaks. One day, a woodpecker finds a particular tree that o

bixtya [17]

Answer:

1. Reflex Conditioning

Explanation:

Conditioning is an aspect of learning where a stimulus works effectively in producing a response from an organism. This response becomes regular given the type of reinforcement that is administered to the organism. The reinforcement is usually a reward that is given to the organism.

This is what is observed in the woodpecker. The stimulus or reinforcement which proves effective in producing a continuous response from the woodpecker is the abundant supply of the birds favorite bugs. This reinforcement makes it possible for the woodpecker to become conditioned towards returning to the tree.

4 0

3 years ago

If the half-life of hydrogen-3 is 11.8 years, after two half-lives the radioactivity of a sample will be reduced to one-half of

maw [93]

Answer:

False

Explanation:

Half life is the time period at which the concentration of the radioactive substance in decay reduced to half.

<u>Thus, if the hydrogen-3 has gone 2 half lives, it means that it has first reduced to its half and then again the half of what it was, i.e. 1/4</u>

Thus, after two successive half-lives, the concentration must be 1/4 of the initial concentration and hence, the statement is false.

4 0

3 years ago