10) Quantas combinações de duas cores podemos fazer com as cores verde, azul, amarelo,

Which statement is true about this function h(x) = 2^x-5

Marysya12 [62]

Answer:

$\frac{1}{32} x$

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If 30 kids in the class like grape juice, how many kids like pineapple juice?

lbvjy [14]

Sorry, I'm going to need a more accurate question. How many kids are there in total?

5 0

3 years ago

Can anyone help me with this

yaroslaw [1]

Answer:

answer is 11 feet is the correct answer

5 0

3 years ago

A circular pool is 3.5 meters deep and has a radius of 9 meters. What is the volume

mote1985 [20]

Answer:

$890.75m^3$

Step-by-step explanation:

Step one:

given data

heigth/depth = 3.5m

radius= 9m

Step two:

The shape is that of a cylinder

Hence the volume of the pool is

$V= \pi r^2h$

substitute

$V= 3.142*9^2*3.5\\\\V=890.75 m^3$

7 0

3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

3 years ago