Answer:
Step-by-step explanation:
1) 2x -y = 1 -------1
3x - y = -6 ------2
Subtract eqn 2 from eqn 1
-x = 1--6 = 7
x = -7
Put x= -7 in eqn 1
2*-7-y = 1
-14-y = 1
- y = 15
y = -15
2) 4x +2y = 10------1
y = 4x + 2--------2
Put eqn 2 in eqn 1
4x + 2 ( 4x+ 2) = 10
4x + 8x + 4 = 10
12x = 6
x = 6/12 = 1/2
Put x = 1/2 in eqn 2
y = 4* 1/2 + 2= 2 + 2
= 4
3) 6x - y = 2------1
y = 3x + 4---------2
Put eqn 2 in eqn 1
6x - (3x +4) = 2
6x - 3x - 4 = 2
3x = 6
x = 2
y = 3*2 + 4 = 6 + 4
= 10
<h2>
Explanation:</h2>
As I understand, the given equation is:
So we need to write this into general form. The general form of the equation of a line is given by:
Where A and B can't be zero at the same time. So subtracting 5y from both sides:
Answer:
Multiply each as in like 120 multiply by 1.2. If 60 multiply by 0.6.
Step-by-step explanation:
Cos(angle) = Adjacent Leg / Hypotenuse
cos(35) = 9 / x
x = 9 / cos(35)
x = 10.99
Rounded to nearest tenth = 11.0
