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3 years ago

What is 3/250 as a decimal?

Mathematics

2 answers:

tatyana61 [14]3 years ago

8 0

Hello noble user
Here is your answer
0.01
Good luck!

yarga [219]3 years ago

5 0

Wait it's actually 0.012

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Suppose that $6500 is placed in an account that pays 17% interest compounded each year. Assume that no withdrawals are made from

MatroZZZ [7]

Answer: $7,605

Step-by-step explanation:

At the end of 1 years, the amount in the account will be:

= Principal * (1 + rate)^ no. of periods

= 6,500 * (1 + 17%)

= $7,605

4 0

3 years ago

Gavin’s gross pay is $3851. his deductions total is $756.72. what percent of his gross pay is take home pay.

kvv77 [185]

Gross pay - Total deductions = net pay

$3851-$756.72 = $3094.28

Divide total net pay by 7(days) = $442.04

7 0

4 years ago

A person drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed f

Olin [163]

Answer:

$\chi^2 = \frac{(26-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33}+\frac{(44-33.33)^2}{33.33}+\frac{(37-33.33)^2}{33.33}+\frac{(27-33.33)^2}{33.33}+\frac{(34-33.33)^2}{33.33}=6.7$

Now we can calculate the degrees of freedom for the statistic given by:

$df=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >6.7)=0.244$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we can conclude that the outcomes are equally likely

Step-by-step explanation:

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the frequencies

H1: There is a difference in the frequencies

The level of significance assumed for this case is $\alpha=0.01$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The observed values are:

Value 1 2 3 4 5 6

Frequency 26 32 44 37 27 34

And the expected values are for this case the same $E_i = \frac{200}{6}= 33.33$

And now we can calculate the statistic:

$\chi^2 = \frac{(26-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33}+\frac{(44-33.33)^2}{33.33}+\frac{(37-33.33)^2}{33.33}+\frac{(27-33.33)^2}{33.33}+\frac{(34-33.33)^2}{33.33}=6.7$

Now we can calculate the degrees of freedom for the statistic given by:

$df=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >6.7)=0.244$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we can conclude that the outcomes are equally likely

7 0

4 years ago

Butoxors [25]

Answer:

soulutions

0,03| = 3×1^100 × 1× 1^1000

=3^100 + 1^1000

=30^1000 + 1^1000

=31^1000

(3=3×10 =30 )

(100 1000 1000 )

4 0

2 years ago

Find the smallest integer value of X that satisfies the inequality of 6X>7

Nastasia [14]

Answer:

x = 2

Step-by-step explanation:

The solution set can be found by dividing the inequality by the coefficient of x.

6x > 7

x > 7/6

The smallest integer greater than 7/6 is 12/6 = 2.

The smallest integer solution is x = 2.

5 0

3 years ago