Answer:
The missing length is 12 ft.
Step-by-step explanation:
If you compare the length to the already indentified vertical lengths, you can use 8ft and 4ft, which added together is the missing length.
Step 1: Find f'(x):
f'(x) = -6x^2 + 6x
Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:
f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12
Step 3: Find f(2), so you have a point on y=f(x):
f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4
So, you have the point (2,-4) and the slope of -12.
Step 4: Find the equation of your tangent line:
Using point-slope form you'd have: y + 4 = -12 (x - 2)
That is the equation of the tangent line.
If your teacher is picky and wants slope-intercept, solve that for y to get:
y = -12 x + 20
Hypotenuse = 9cm^2+ 13cm^2
=81 +169
=250
= \{250}(find the square root)
=16cm^2(hypotenuse)
Answer:
9 - (1/2)^4 x48
9 - 1/16 x 48
9 - 3 = 6
Step-by-step explanation:
