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kondor19780726 [428]
3 years ago
15

If I play video-games 5 hours a day, every day, how long would it take to have 1,500 hours of playtime? I would like to know how

to solve the problem as well, thanks.
Mathematics
2 answers:
Lelu [443]3 years ago
6 0

Answer:

300

Step-by-step explanation:

5÷1500=300

5×3=15

15-15=0

0000

300×5=1500

sorry this the best way I know how to explain

solmaris [256]3 years ago
5 0

Answer:

Step-by-step explanation:

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What is the distance between the points 4 and -5 on a number line?
Ket [755]

Answer:

9

4--3--2--1--0--1--2--3--4--5

Positive        Negative

Step-by-step explanation:

6 0
2 years ago
Linear model function
sveticcg [70]

Using equations of linear model function, the number of hours Jeremy wants to skate is calculated as 3.

<h3>How to Write the Equation of a Linear Model Function?</h3>

The equation that can represent a linear model function is, y = mx + b, where m is the unit rate and b is the initial value.

Equation for Rink A:

Unit rate (m) = (35 - 19)/(5 - 1) = 16/4 = 4

Substitute (x, y) = (1, 19) and m = 4 into y = mx + b to find b:

19 = 4(1) + b

19 - 4 = b

b = 15

Substitute m = 4 and b = 15 into y = mx + b:

y = 4x + 15 [equation for Rink A]

Equation for Rink B:

Unit rate (m) = (39 - 15)/(5 - 1) = 24/4 = 6

Substitute (x, y) = (1, 15) and m = 6 into y = mx + b to find b:

15 = 6(1) + b

15 - 6 = b

b = 9

Substitute m = 6 and b = 9 into y = mx + b:

y = 6x + 9 [equation for Rink B]

To find how many hours (x) both would cost the same (y), make both equation equal to each other

4x + 15 = 6x + 9

4x - 6x = -15 + 9

-2x = -6

x = 3

The hours Jeremy wants to skate is 3.

Learn more about linear model function on:

brainly.com/question/15602982

#SPJ1

5 0
1 year ago
What is the solution set to the inequality
creativ13 [48]

(4x - 3)(2x - 1) \geqslant 0 \\ \Leftrightarrow \begin{cases}4x - 3 \geqslant 0 \\ 2x - 1 \geqslant 0\end{cases}\: \vee \:\begin{cases}4x - 3 \leqslant 0 \\2x - 1 \leqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant  \frac{3}{4}  \\ x  \geqslant  \frac{1}{2} \end{cases}\: \vee \:\begin{cases}x\leqslant  \frac{3}{4}  \\x \leqslant  \frac{1}{2}  \end{cases} \\ \Leftrightarrow x \geqslant  \frac{3}{4} \: \vee \: x \leqslant  \frac{1}{2}  \\ \Rightarrow The\: third\: option

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2 years ago
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The two points are
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