Answer:
9,4,-1,-6
Step-by-step explanation:
You just need to plug in the x values into the equation and solve.
Answer:
y=35
Step-by-step explanation:
y in (-oo:+oo)
14 = (2*y)/5 // - (2*y)/5
14-((2*y)/5) = 0
(-2/5)*y+14 = 0
14-2/5*y = 0 // - 14
-2/5*y = -14 // : -2/5
y = -14/(-2/5)
y = 35
y = 35
Answer:
Fuel used = 111,303,473,760 MJ/year
Step-by-step explanation:
Power production = Fuel energy * Efficiency
1200 MW = Fuel energy * 0.34
Fuel energy = 1200 MW / 0.34 =3529.41 MW
This means it consumes 3529.41 MJ/s.
Per year, it operates 365 days, 24 hours a day, 3600 seconds an hour.
To calculate the fuel used annualy we have to multiplicate by all these factors
Fuel used = 3529.41 MJ/s * 3600 s/hour * 24 hours/day * 365 days/year
Fuel used = 111,303,473,760 MJ/year
If data for a time series analysis are collected on an annual basis only, then the option(b) seasonal pattern can be ignored
Time series analysis is a specific way of analyzing a sequence of data points collected over an interval of time
The seasonal pattern is refers to the seasonal characteristics of the time series data. It is the predictable pattern that repeats at a certain frequency within one year, such as weekly, monthly, quarterly, etc.
A horizontal pattern exists when the data fluctuate randomly around a constant mean over time.
A trend pattern exists when there is a long-term increase or decrease in the series.
The cyclical component of a time series refers to fluctuations around the trend, excluding the irregular component, revealing a succession of phases of expansion and contraction
Here, the data for a time series analysis are collected on an annual basis, so the seasonal pattern can be ignored
Learn more about Time series analysis here
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