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3 years ago

Please answer and explain. 25pts

Mathematics

2 answers:

AVprozaik [17]3 years ago

7 0

C) x<8 and x>10
c) all real Numbers (multiply the -2 to the parenthesis and you get the same equation on both sides which means all real numbers)
C) x is greater than or equal to -3 (solid circle with the line towards positive.)
A) 24 ( distribute then subtract p from both sides)
B) d-12 $\geq$ 51; d $\geq$ 63

mash [69]3 years ago

7 0

Answer:

i don't kno sorry i couldn't help

Step-by-step explanation:

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Select all equations that match the tape diagram.

patriot [66]

Answer:

6x+8=35

35=8+6x

Step-by-step explanation:

id.k about 35=8+x+X+X+x+X+x

5 0

2 years ago

X-1=y what is the answer plz give me the answer

guajiro [1.7K]

Answer:

First of all, observe that this is a line, since you can rewrite the equation as y−x+1=0 , which follows the pattern of the generic line ax+by+c=0 .

To draw a line you need two of its points, which you can connect.

To find two points, you can plug any value for one variable, and solve for the other.

For example, let's choose

x=0 . The equation becomes

0−1=y , and so y=−1 .

The first point is thus (0,−1).

Then, let's choose

x=1 . The equation becomes 1−1=y , and so y=0 . The first point is thus

(1,0).

Now you only need to draw the points

(0,−1)

Step-by-step explanation:

Hope it is helpful...

6 0

3 years ago

Select the correct word to describe the function. the equation y = startfraction 5 x cubed over 8 endfraction represents functio

balandron [24]

The functions and their descriptions are:

Polynomial: $y = \frac{5x^3}{8}$ and $y = 5x^3 + 8$
Logarithm: $y = 6 + 0.25\ln(x)$
Exponential $y = \frac{18}{1 + 6e^{-0.25x}}$

<h3>How to describe the functions?</h3>

The functions are given as:

$y = \frac{5x^3}{8}$

$y = 6 + 0.25\ln(x)$

$y = \frac{18}{1 + 6e^{-0.25x}}$

$y = 5x^3 + 8$

The functions would be described based on the type of function they represent.

Functions that use the "ln" keyword are logarithmic functions, while functions that use the "e" keyword are exponential functions.