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gladu [14]
3 years ago
8

He repartido mi colección de canicas entre mis tres amigos. A thales le he dado 1/5 del total, a arquimedes un 1/3 del resto y p

or último a pitagoras le he regalado las 16 canicas que me quedaban
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

Ok, supongamos que en total hay N canicas.

1/5 de esas canicas se le dieron a Thales.

Entonces el resto ahora es:

1 - 1/5 = 4/5.

1/3 de esas canicas se le dieron a Arquimedes.

Entonces Arquimedes recibe:

(1/3)(4/5) = 4/15 de las canicas totales.

El resto, que eran 16, se le dieron a Pitagoras.

Ahora, las dos primeras entregas fueron:

1/5 + 4/15 = 3/15 + 4/15 = 7/15.

El resto seria:

1 - 7/15 = 8/15.

Y sabemos que el resto es igual a 16 canicas, entonces tenemos que:

(8/15)*N = 16.

De aca podemos calcular el numero total de canicas.

N = 16*(15/8) = 30

Esto quiere decir que inicialmente hay 30 canicas.

Thales recibe 30*(1/5) = 7 canicas.

Arquimedes recibe 30*(4/15) = 8 canicas.

Pitagoras recibe 16 canicas.

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The smallest prime number of p for which p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.

<h3>What is the smallest prime number of p for which p must have exactly 30 positive divisors?</h3>

The smallest number of p in the polynomial equation p^3 + 4p^2 + 4p for which p must have exactly 30 divisors can be determined by factoring the polynomial expression, then equating it to the value of 30.

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