The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation 
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2=0
=> =0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
Answer:
$2046
Step-by-step explanation:
Add 1947 and 99 because he is depositing, as in adding, 99 dollars
Hello!
The total measure of the angles in a triangle always add up to 180 degrees.
The measures that you are given are 37 and 82 degrees. To find what angle x equals, we must first add together the angles that we know:
37 + 82 = 119
To find angle x, we simply subtract 119 from the total number of degrees (180):
180-119 = 61
The measure of angle x is 61 degrees.
I hope this helps you! Have a fantastic day!
Answer:
2097152 is the answer to your question
-6x-4(-7x-13)=-58
Multiply the bracket by -4
-6x-4(-7)-4(-13)= -58
-6x+28x+52= -58
22x+52= -58
Move +52 to the other side. Sign changes from +52 to -52.
22x+52-52= -58-52
22x= -110
Divide by 22.
22/22x= -110/22
x= -5
Answer: x= -5
