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podryga [215]
3 years ago
7

Help plss, i will brainliested :)

Mathematics
1 answer:
Komok [63]3 years ago
5 0

Answer: Look at the photo. :)

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Select the expressions that are equivalent to 7(7w).
Jet001 [13]

Answer:

answers are A and C

Step-by-step explanation:

they both will equal 49w

Please Brainliest will be much appreciated

3 0
3 years ago
Find the midpoint of a line segment with given endpoints (4,-5) and (-6,3)
Mashcka [7]
The equation for the midpoint of a line segment is ( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}). Thus, the midpoint of this segment is (\frac{4 + (-6)}{2}, \frac{-5 + 3}{2}) = \boxed{(-1, -1)}.
3 0
4 years ago
The sum of 11.6 and 4.1 by rounding each number to the nearest whole.
Karo-lina-s [1.5K]
11.6 rounded to the nearest whole is 12 and 4.1 rounded to the nearest whole is 4 (rule is if the decimal [or number in general] is 4 or lower, the whole stays the same and if the number is 5 or higher, the whole goes up by one). 12+4=16
3 0
2 years ago
The function models the number of accidents per 50 million miles driven as a function
sesenic [268]

Answer:

x=39, y=180

Step-by-step explanation:

f(x)=0.4x²-31.2x+788.4

For x=39 the graph reaches its lowest point.

The minimum value of y is:

x=39→y=f(39)=0.4(39)²-31.2(39)+788.4

y=f(39)=0.4(1,521)-1,216.8+788.4

y=f(39)=608.4-1,216.8+788.4

y=f(39)=180

5 0
4 years ago
The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the func
Hunter-Best [27]

Answer:

<em>A) (-5,7)</em>

Step-by-step explanation:

<u>Functions and Relations</u>

A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

\boxed{A)\ (-5,7)}

8 0
4 years ago
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