Answer:
x=1
Step-by-step explanation:
According to your typed question,
f(x)=2x-3
Let f(x)=y
y=2x-3
Now,
Interchanging the positions of x and y
x=2y-3
x+3=2y
x+3/2=y
f'(x)=x+3/2
Then,
f(x)=f'(x)
2x-3=x+3/2
2(2x-3)=x+3
4x-3=x+3
4x-x=3+3
3x=3
x=3/3
x=1
According to your image question,
f(x)=x/2x-3
f(x)=f'(x)
Now,
Let y=f(x)
y=x/2x-3
y(2x-3)=x
2xy-3=x
2xy-x=3
x(2y-1)=3
2y-1=3x
2y=3x+1
y=3x+1/2
f'(x)=3x+1/2
Then,
f(x)=f'(x)
x/2x-3=3x+1/2
2x=6xsq+2x-9x+3
2x=6xsq+7x+3
solve for x ok
Its 2x^2-4x, to check it add it to 3x^2-2x or
2x^(2)-4x+3x^(2)-2x
B) x=2 and y=14 i’m pretty sure lol
No not always. hope this helps have a nice day
Answer:
1.048576e+46
Step-by-step explanation:
(5x5)x20x80 to the power of 10
(25x20)x80 to the power of 10
500x80 to the power of 10
40000 to the power of 10
the answer is 1.048576e+46
