The value of y in the triangle is 6°.
<h3>How to calculate the value of y in the triangle?</h3>
Firstly, it's important to note that a triangle has the total angles of 180°.
Based on the information, the triangle has interior angle measures of 11y, 10y + 10°, and 10y - 16º.
The value of y in the triangle will be illustrated thus:
11y + 10y + 10 + 10y - 16 = 180
31y - 6 = 180
31y = 180 + 6.
31y = 186
Divide.
y = 186 / 31
y = 6
The value of y is 6.
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Are there answer choices for this one because I got something kind of weird
The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation 
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2=0
=> =0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
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Answer:
The answer is D. 7
Step-by-step explanation:
the degree of polynomial is 7
