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Afina-wow [57]
3 years ago
13

What would happen to the slope of the graph of y=2/3×-3 if the line were shifted 6 units up?

Mathematics
1 answer:
yaroslaw [1]3 years ago
5 0

The slope wouldn't change, but the y-intercept would become 3 because you add -3 to 6

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D)graph c

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2 years ago
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Juli2301 [7.4K]

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option 2 is correct

Step-by-step explanation:

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3 years ago
Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the d
jolli1 [7]

Answer:

Segment EH and segment E prime H prime both pass through the center of dilation (A)

The complete question related to this found on brainly (ID:16812154) is stated below:

Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the dilation?

E(0,5) F(1,1) G(-2,1) H(0,1)

a) segment EH and segment E prime H prime both pass through the center of dilation.

b)The slope of segment EF is the same as the slope of segment E prime H prime.

c) segment E prime G prime will overlap segment EG. segment

d) EH ≅ segment E prime H prime.

Step-by-step explanation:

∆EFG = Original image

∆EFG is dilated to give ∆E'F'G'

∆E'F'G' = New image

Scale factor = 3

Center of dilation = (0,1) = H(0,1)

Coordinates ∆EFG : E(0,5) F(1,1) G(-2,1)

To determine the statement that is true about the dilation from the options,

First we would make a diagram on the coordinates of ∆EFG and center of dilation (H).

Find attached the diagram.

Length GF = 3unit

Length G'F' = 3×scale factor = 9unit

Length EH = 4unit

Length E'H' = 4×scale factor = 12unit

Then we would move 3units to the left on same line from G to get the coordinate of G'(mark the point).

Also move 3units to the right on same line from F to get the coordinate of F'(mark the point).

Both of these give length of G'F' = 9unit

Now move 8units to the top from E to get the coordinate of E'(mark the point).

From this you get length E'H' = 12unit

Draw lines connecting the three points to get ∆E'F'G'

See diagram for better understanding

From the diagram, EH and E'H' both pass through (0,1). The other options are wrong.

Therefore, Segment EH and segment E prime H prime both pass through the center of dilation (A)

5 0
3 years ago
Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r
Rainbow [258]

Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>
  • Since the degree of given polynomial is 4
  • Therefore it must have four roots.
  • Already given that the given polynomial has 1 positive real root and 1 negative real root .
  • Every polynomial with degree greater than 1  has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

8 0
3 years ago
Whats equivalent to 3.5 x 100.
ioda

Answer:

350

Step-by-step explanation:

since there are 2 zeros in "100", move the decimal over 2 places

4 0
3 years ago
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