The area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.
<h3>How to find the area of a sector?</h3>
1) The formula for area of a sector of a circle is;
A = (θ/360) * πr²
where πr² is area of circle
θ is the angle subtended by the sector
Thus, we conclude that the area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.
2) The area of the triangle formed as part of the segment is subtracted from from the area of the sector.
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Answer:
y = 27
Step-by-step explanation:
y/3 + 2 = 11
First subtract 2 from each side
y/3 + 2-2 = 11-2
y/3 = 9
Then multiply each side by 3
y/3 *3 = 9*3
y = 27
Answer:
-2x + 1
Step-by-step explanation:
3 + 7x - (2 + 9x)
Distribute the negative:
3 + 7x - 2 - 9x
Combine like terms:
-2x + 1
Answer:
The record alligator is
feet longer than the alligator Taylor saw.
Step-by-step explanation:
Taylor saw an American alligator at a zoo that measured
feet long. The record length of an American alligator is
feet long. How much longer is the record alligator than the alligator Taylor saw?
For this first convert the mixed fraction into an improper fraction.


Now subtract
from
.

Hence, the record alligator is
feet longer than the alligator Taylor saw.
Answer:
C.$0.15 I TOOK IT ON STUDY ISLAND
Step-by-step explanation:
First, you want to find an exact point on the graph. What I mean by this is you want to go somewhere on the graph where the line goes through an exact y and x value.
Second, you want to figure out where this x and y value are. Where the graph first goes through two points is at (20, 3).
Third, you want to figure out what the 20 and the 3 mean. 20 is the number of messages and 3 is the dollar amount.
Finally, to calculate the amount of money per message, you divide the dollar amount (3) by the number of messages (20). So, you have 3/20. After this, simplify 3/20 to get 0.15, or 15 cents per message.