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trapecia [35]
3 years ago
14

(102-38) x 14+7+162=

Mathematics
2 answers:
Mila [183]3 years ago
7 0
12,810 I think. Hope this helps
bezimeni [28]3 years ago
4 0

Answer:

=64x^14+169

Step-by-step explanation:

happy to help ya :)

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A square has an area of 64 m². What is the length of each side?
anygoal [31]

Answer:

8m

Step-by-step explanation:

The area of a square is length*width.

We can square root the area to get the length of each side. Since the shape is a <em>square</em>, the lengths are the same.

\sqrt{64}=8

One side is <u>8m</u>.

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3 years ago
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A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%
IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18

a) P(firm will make at least one hire)

P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32

Also,

P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4

\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9

b) expected value and the standard deviation of the number of hires.

E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58

E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89

7 0
3 years ago
What are all of the factors for 12 and 30? If you answer thank you for helping, I really appreciate it.
svet-max [94.6K]

Answer:

12

2,3,4,6

30

12,3,5,6,10,15

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3 years ago
Lori u there? it's me alex
liubo4ka [24]

Answer:

hi

Step-by-step explanation:

6 0
3 years ago
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