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nikklg [1K]
3 years ago
13

Please help me with this I will give brainleist:):)

Mathematics
1 answer:
lara31 [8.8K]3 years ago
4 0
Y intercept is +1
Slope is 1/2
Y= 1/2x + 1
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A spin balancer rotates the wheel of a car at 500 revolutions per minute. If the diameter of the wheel is 26 inches, what road s
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c. 52 rad/s

Step-by-step explanation:

Final question does not correspond with available option. The real question is: <em>What is the angular speed in radians per second?</em>

At first we assume that spin balance rotates at constant rate and convert given angular speed, measured in revolutions per minute, into radians per second:

\omega = \left(500\,\frac{rev}{min} \right)\cdot \left(2\pi\,\frac{rad}{rev} \right)\cdot \left(\frac{1}{60}\,\frac{min}{sec}  \right)

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The number of fruit snacks available per student varies inversely with the number of students. There are 10 fruit snacks for eac
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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
sladkih [1.3K]

Answer:

(a) The probability that a randomly selected adult is either overweight or obese is 0.569.

(b) The probability that a randomly selected adult is neither overweight nor obese is 0.431.

Step-by-step explanation:

Let <em>A</em> = a person is over weight and <em>B</em> = a person is obese.

The information provided is:

An adult is considered overweight if the BMI ≥ 25 but BMI < 30.

An obese adult will have a BMI ≥ 30.

According to the range of BMI the events A and B are independent.

P (A) = 0.331 and P (B) = 0.357.

(a)

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P (A ∪ B) = P (A) + P (B) - P (A ∩ B)

               = P (A) + P (B) - P (A)×P (B)

               =0.331+0.357-(0.331\times0.357)\\=0.569833\\=0.569

Thus, the probability that a randomly selected adult is either overweight or obese is 0.569.

(b)

Compute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(A^{c}\cup B^{c})=1-P(A\cup B)=1-0.569=0.431

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.431.

4 0
4 years ago
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