Compute the probability of randomly selecting a three or club.

1 answer:

5 0

Find the total number of cards in a deck. Count all the # 3’s total cards/#3 cards
Count all the clubs total card/ clubs
Not sure if you are counting 3’s & clubs together. If you are, total cards/ both
So all you have to do is count & then divide to get the probability.

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(4-1)

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Step-by-step explanation:

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Which function is graphed on the right?

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Answer: $y=2^{x-2}+3$

Step-by-step explanation:

To find the equation from a graphed function, you can substitute points into each equation to find the original:

A point on the graph is (2, 4). Substituting this into each equation, we get:

$4=2^{2+3} -2$ , which claims that 4 is equal to 30, which is incorrect.

$4=2^{2-3} +2$ , which claims that 4 is equal to 3/2, which is incorrect.

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We can test the third function further by taking another point on the graph, (3, 5), and substituting it into the function:

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3 years ago

10. A bag contains 4 red balls, 6 green balls and some white balls. If the probability of not drawing a white ball in one draw b

klasskru [66]

Answer:

No of white balls = 5

Step-by-step explanation:

Given that,

Total no of red balls = 4

Total no of green balls = 6

The probability of not drawing a white ball in one draw be, $P=\dfrac{2}{3}$

We need to find the number of white balls. Let there are x balls.

The probability of drawing a white ball = 1 - the probability of not drawing a white ball

= 1 -2/3

= 1/3

Using the formula for solving probability of having a white ball.

$P=\dfrac{\text{favorable outcome}}{\text{total no of outcomes}}\\\\\dfrac{1}{3}=\dfrac{x}{4+6+x}\\\\\dfrac{1}{3}=\dfrac{x}{10+x}\\\\10+x=3x\\\\10=2x\\\\x=5$