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Semenov [28]
3 years ago
8

Compute the probability of randomly selecting a three or club.

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0
Find the total number of cards in a deck. Count all the # 3’s total cards/#3 cards
Count all the clubs total card/ clubs
Not sure if you are counting 3’s & clubs together. If you are, total cards/ both
So all you have to do is count & then divide to get the probability.
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URGENTTT<br><br><br> 3+3 x 7^2 - 9 x 10
charle [14.2K]

Answer: 60

Step-by-step explanation:

8 0
3 years ago
In the figure shown below, AC is parallel to DE with transversal BF
densk [106]

Answer:

<h3>X = 142°</h3><h3>Y = 38° </h3>

<em><u>Given </u></em><em><u>-</u></em><em><u> </u></em> AC is parallel to DE

angle 3y + 28 = angle X ( Vertically opposite angles are equal).

3y + 28 = X

X + Y = 180° ( supplementary angles).

3y - X = (-28)

Solving both the equation we get

multiply eq 1 with 3

3x + 3y = 540

-X + 3y = (-28)

subtracting

4x = 568

x = 142°

3y + 28 = 142

3y = 142 - 28

3y = 114

y = 38°

4 0
2 years ago
D is the midpoint of RJ⎯⎯⎯⎯. R has coordinates (−4,7), and D has coordinates (2,−1). Identify the coordinates of J.
Aleksandr [31]

Answer:

(8,-9)

Step-by-step explanation:

If the x-coordinate of R is 6 units away from D's x-coordinate, then so will J's x-coordinate. If the y-coordinate of R is 8 units away from D's y-coordinate, then so will J's y-coordinate.

Side note/Extra information:

The line would be y=\frac{-4}{3} x+\frac{5}{3}

3 0
3 years ago
I will mark you brainlist if you helppp me pls and thankyouuu
Mamont248 [21]

Answer:

1 option is correct nd your answer is also correct

5 0
3 years ago
The first side of a triangle is 3 inches shorter than the second side, and 2 inches longer than the third side. How long is each
ziro4ka [17]

Answer:

the length of the first side of the triangle is \frac{28}{3}\ in

the length of the second side of the triangle is \frac{37}{3}\ in

the length of the third side of the triangle is \frac{19}{3}\ in

Step-by-step explanation:

Let

x-----> the length of the first side of a triangle

y----> the length of the second side of a triangle

z---> the length of the third side of a triangle

we know that

x=y-3

y=x+3 -----> equation A

x=z+3

z=x-3  -----> equation B

The perimeter of the triangle is equal to

P=x+y+z

P=28\ in

so

28=x+y+z -----> equation C

substitute equation A and equation B in equation C

28=x+(x+3)+(x-3)

solve for x

28=3x

x=\frac{28}{3}\ in

Find the value of each side

the first side of a triangle is x

x=\frac{28}{3}\ in

the second side of a triangle is y

y=\frac{28}{3}+3=\frac{37}{3}\ in

the third side of a triangle is z

z=\frac{28}{3}-3=\frac{19}{3}\ in

7 0
3 years ago
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