<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890
:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s =
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
Answer:
-4x*2 - 7y*2 + 4
Step-by-step explanation:
simplify by adding/subtracting the like terms
You can use the equation
to find the lenth of the legs
x = leg 1
x + 14 = leg 2
Four times d to the third minus ten
The equivalent to (1/3)^3 is
(1/3) x (1/3) x (1/3) = .<span>037
</span>
The answer is 1/27 or 0.37.
