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mario62 [17]
3 years ago
13

Suppose f(x)=4x-2 and g(x)=-2x+1

Mathematics
1 answer:
choli [55]3 years ago
3 0
In order to get g(x) you would multiply the equation of f(x) by -1/2.
4x(-1/2)=-2x and -2(-1/2)=1.
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Find the equation of a line tangent to the circle (x−1)^2+y^2=26 at the point (2, −5).
77julia77 [94]

Center of circle is ( 1, 0).

Slope of normal passing though ( 1, 0 ) and ( 2, -5 ) is :

m_p=\dfrac{0-(-5)}{1-2}\\\\m_p=-5

So, slope of tangent will be :

m_t=-\dfrac{1}{m_n}\\\\m_t=\dfrac{1}{5}

Equation of tangent :

y-(-5)=\dfrac{1}{5}(x-2)\\\\5y+25=x-2\\\\5y-x+27=0

Hence, this is the required solution.

6 0
4 years ago
Peter the optician sees 16 patients one Tuesday.4 are neither short nor long sighted,the total number of short sighted patients
My name is Ann [436]

The number of short-sighted patients is 7

The number of long-sighted patients is 5

The number of patients requiring a varifocal lens is 4

Step-by-step explanation:

Stepwise solution-

Throughout the question, only 3 types of patients are mentioned. Hence, it would be safe to assume that he saw/sees these 3 types of patients on Tuesday.

As per the given details-

4 are neither short-sighted patients nor long-sighted patients. Then it means no of varifocal lens patients is 4.

Hence remaining total patients=16-4=12

As given, no of short-sighted patients is 2 more than the number of long-sighted patients.

Let us assume the number of long-sighted patients as “x”

Thus, the number of short-sighted patients would be “x+2”

x+(x+2)=12   (total remaining patients)

2x=10

x=5

Hence, No. of long-sighted outpatients = 5

            No. of short-sighted outpatients =7

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4 years ago
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Answer:

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4 0
4 years ago
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