Answer: 11/12
Step-by-step explanation: hope this helps!
Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
7*9
b. 63
v=5 i=1
5+1+1= 7
x=10
10-1= 9
9*7= 63
Answer:
The graph of f(x) is shifted k units to the right of the graph of g(x).
Step-by-step explanation:
Given the function and where k <0.
As, horizontal depends on the value of x and are when
g(x)=f(x+h) graph shifted to left.
g(x)=f(x-h) graph shifted to right.
Now, given
But here k is negative, when k is considered positive then f(x) becomes
⇒ The graph of f(x) is shifted k units to the right of the graph of g(x).
Correct option is B.