$Use\ \cos.\\\\\cos24^o=\dfrac{11}{x}\\\\\cos24^o\approx0.9135\\\\\dfrac{11}{x}\approx0.9135\ \ \ |cross\ multiply\\\\0.9135x\approx11\ \ \ \ |divide\ both\ sides\ by\ 0.9135\\\\x\approx12$

7 0

2 years ago

A population of values has a normal distribution with μ = 155.4 and σ = 49.5 . You intend to draw a random sample of size n = 24

xz_007 [3.2K]

Answer:

(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.

(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.

Step-by-step explanation:

Let the random variable X follow a Normal distribution with parameters μ = 155.4 and σ = 49.5.

(a)

Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

$P(158.6 < X$

*Use a standard normal table.

Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.

(b)

A sample of n = 246 is selected.

Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

$P(158.6 < \bar X$

*Use a standard normal table.

Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.

4 0

2 years ago

Read 2 more answers

Solve: VII multiplied by IX. Show your answer in standard form.

matrenka [14]

7*9
b. 63

v=5 i=1
5+1+1= 7

x=10

10-1= 9

9*7= 63

8 0

2 years ago

HELP PLEASE!!!

True [87]

Answer:

The graph of f(x) is shifted k units to the right of the graph of g(x).

Step-by-step explanation:

Given the function and where k <0.

As, horizontal depends on the value of x and are when

g(x)=f(x+h) graph shifted to left.

g(x)=f(x-h) graph shifted to right.

Now, given

But here k is negative, when k is considered positive then f(x) becomes

⇒ The graph of f(x) is shifted k units to the right of the graph of g(x).

Correct option is B.

6 0

3 years ago