Answer:
a₁₀₀ = 697
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 4 and d = a₂ - a₁ = 11 - 4 = 7 , then
a₁₀₀ = 4 + (99 × 7) = 4 + 693 = 697
Five sixths of the sum of three consecutive numbers is -237.5 write an equation and solve
1 answer:
You might be interested in