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Vitek1552 [10]
3 years ago
8

Write a formula for the nth term of these geometric sequences. a4 = 6, a5 = 12

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0
(1.5)4 = 6, (2.4)5 = 12
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How do I do this problem??
Crank
Expanding 8x^3, we multiply 8*8 and x^3 by x^3 to get 64x^6. Since we know that the cube root of 64 is 4, we can separate that. Next, since you add exponents while multiplying, 6/3 is the exponent for the cube root of x^6=x^2. Therefore, your answer is 4x^2
5 0
3 years ago
If Fred’s age now is three times what it was 12 years ago, how old is Fred 12 years ago?
Nikitich [7]

Answer:

6

Step-by-step explanation:

12+x=3x

2x=12

x=6

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2 years ago
Help me I need answers?:
JulsSmile [24]

Answer:

46.5 cm

Step-by-step explanation:

63 ÷ 2= 31.5 + 15 = 46.5

4 0
3 years ago
What 3 numbers give the same result when multiplied and added together? How do you know?
ella [17]

Answer:

1,2 and 3 because this three are positive numbers and when added and multipled both gives the same answer 6. 1,2 and 3 are the positive integers and the result of their addition and their multiplication is same .

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Rewrite the quadratic function in vertex form.<br> Y=3x^2-12x+4
chubhunter [2.5K]

Answer:

\large\boxed{y=3(x-2)^2-8}

Step-by-step explanation:

The vertex form of an equation of a parabola y = ax² + bx + c:

f(x)=a(x-h)^2+k

(h, k) - vertex

h=\dfrac{-b}{2a},\ k=f(h)

We have the equation:

y=3x^2-12x+4\\\\a=3,\ b=-12,\ c=4

Substitute:

h=\dfrac{-(-12)}{2(3)}=\dfrac{12}{6}=2\\\\k=f(2)=3(2^2)-12(2)+4=3(4)-24+4=12-24+4=-8

Finally:

y=3(x-2)^2+(-8)=3(x-2)^2-8

4 0
3 years ago
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