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Sunny_sXe [5.5K]
3 years ago
7

Can I have help please I am stuck on this question it would mean the world if u helped me have a nice day! =) <3

Mathematics
1 answer:
guajiro [1.7K]3 years ago
5 0

Answer:

F

Step-by-step explanation:

1m = 100cm

0.8m = 100*0.8 = 80cm

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Hoochie [10]

Answer:

The system of equations has one solution. The two equations are intersecting lines.

Step-by-step explanation:

if you want to use the substitution method, you would have to plug in y for 12x+2 in the second equation.

2(12x+2)=x+4

next, you have to distribute

24x+4=x+4

subtract 24x from each side

4=-23x+4

subtract 4 from each side

0=23x

divide each side by 23

x=0

now, plug in 0 to one equation.

y=12(0)+2

y=2

the lines intersect at one point, (0,2)

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3 years ago
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Serggg [28]
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3 years ago
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lilavasa [31]

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Step-by-step explanation:

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3 years ago
Two dice are rolled. Use the complement rule to find that the probability that the sum of the dice is less than 10.
Katarina [22]

Answer:

\dfrac{5}{6}

Step-by-step explanation:

When two dice are rolled, the sample space is

\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}

In total, 36 outcomes

First, find the probability that the sum is 10 or greater:

All favorable outcomes

10: (4,6),\ (5,5),\ (6,4)

11: (5,6),\ (6,5)

12: (6,6)

In total, 6 outcomes.

The probability that the sum is 10 or greater is

P(A)=\dfrac{6}{36}=\dfrac{1}{6}

Use the complement rule to find that the probability that the sum of the dice is less than 10:

P(A^C)=1-P(A)=1-\dfrac{1}{6}=\dfrac{5}{6}

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3 years ago
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