Can I have help please I am stuck on this question it would mean the world if u helped me have a nice day! =) <3
1 answer:
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Replace x with -3 and add
y = -x+1
y = -( x ) + 1
y = -( -3 ) + 1 .... replace x with -3
y = 3 + 1 ... two negatives cancel to make a positive
y = 4
So the number 4 goes right next to -3. This means the point (x,y) = (-3,4) is on the line. This is shown as point A on the attached image below.
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Repeat for x = -1
y = -x + 1
y = -( x ) + 1
y = -( -1) + 1 ... replace x with -1
y = 1 + 1
y = 2
So the point (-1,2) is also on the line. This is shown as point B.
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Repeat for x = 0
y = -x + 1
y = -0 + 1 ... replace x with 0
y = 1
So (0,1) is on the line. This is point C.
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Finally, plug in x = 4
y = -x + 1
y = -4 + 1 ... replace x with 4
y = -3
So (4,-3) is on the line, shown as point D.
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After you have at least 2 points plotted on the coordinate grid, you would draw a straight line through those points. Note how points A,B, C, & D are all on the same straight line. The slope of this line is -1 meaning you go down 1 unit each time you move to the right 1 unit. The y intercept is 1, which is where the blue line crosses the y axis.
The question is incomplete. Here is the complete qeustion.
In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15
(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.
(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?
Answer: (a) 0.089 ≤ μ ≤ 0.171
(b) No
Step-by-step explanation:
(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample
X =
X = 0.13
s =
s = 0.029
The degrees of freedom is
N - 1 = 7 - 1 = 6
And since the confidence is of 99%:
α = 1 - 0.99 = 0.01
α/2 = 0.01/2 = 0.005
The t-test statistics for is 3.707
(Value found in the t-distribution table)
Now, calculate Error:
E = .
E = 3.707.
E = 0.041
The interval will be:
0.13 - 0.041 ≤ μ ≤ 0.13+0.041
0.089 ≤ μ ≤ 0.171
(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.