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3 years ago

PLEASE HELP!! ILL GIVE BRAINLIEST

Mathematics

2 answers:

ikadub [295]3 years ago

8 0

<h3>Answer: SSS</h3>

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Explanation:

The left slanted side of the smaller triangle is 2 units long. The left slanted side of the larger triangle is 2+2 = 4 units long. The jump from small to large is "times 2".

The same applies when focusing on the right slanted sides for each triangle.

The horizontal pieces also have this same rule applied when going from 4 to 8.

Therefore, the larger triangle's sides are twice as long compared to the smaller triangle's sides.

This is another way of saying that the ratio large/small is equal to 2, and why the SSS similarity theorem works here.

Nadya [2.5K]3 years ago

3 0

Answer:

ok now give me brainleist...

Step-by-step explanation:

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hammer [34]

Answer:

slope=4root5

Step-by-step explanation:

H^2=b^2+ h^2

(8)^ +(4)^

= 64+16

H^ =80

H= ROOT 80

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4 years ago

Sean lives about 15.5 miles from the airport . Which number rounds to 15.5 when rounded to the nearest tenth.

VashaNatasha [74]

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4 years ago

5×(3-2)=, what is itin expanded form, Explain

Juli2301 [7.4K]

I hope this helps you

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3 years ago

Sin(A+B) sin(A-B) /sin^A Cos^B=1-cot^A Tan^B

telo118 [61]

In order to prove

$\dfrac{\sin(x+y)\sin(x-y)}{\sin^2(x)\cos^2(x)}=1-\cot^2(x)\tan^2(y)$

Let's write both sides in terms of $\sin(x),\ \sin^2(x),\ \cos(x),\ \cos^2(x)$ only.

Let's start with the left hand side: we can use the formula for sum and subtraction of the sine to write

$\sin(x+y)=\cos(y)\sin(x)+\cos(x)\sin(y)$

and

$\sin(x-y)=\cos(y)\sin(x)-\cos(x)\sin(y)$

So, their multiplication is

$\sin(x+y)\sin(x-y)=(\cos(y)\sin(x))^2-(\cos(x)\sin(y))^2\\=\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)$

So, the left hand side simplifies to

$\dfrac{\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now, on with the right hand side. We have

$1-\cot^2(x)\tan^2(y)=1-\dfrac{\cos^2(x)}{\sin^2(x)}\cdot\dfrac{\sin^2(y)}{\cos^2(y)} = 1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now simply make this expression one fraction:

$1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}=\dfrac{\sin^2(x)\cos^2(y)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

And as you can see, the two sides are equal.

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4 years ago

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lesya [120]

The answer is $36

hope this helped :)
alisa202

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4 years ago

Read 2 more answers