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Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
60
Step-by-step explanation:
In the function, the growth factor is "a", the base of the exponent. When the exponent is increased by 1, the value is multiplied by "a".
f(7) = a·f(6) = 4·15
f(7) = 60
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As you know, the exponent signifies repeated multiplication. So, an increase of 1 in the exponent means the base is part of the product one more time:
a^6 = a·a·a·a·a·a
a^7 = a·a·a·a·a·a·a = a·(a^6)
The answer is 60 it was easy
Answer:
x = 5/7
Step-by-step explanation:
4 (0.25 - 2) = x - 0.75 (16 - 8x)
1 - 8 = x - 12 + 6x
1 - 8 + 12 = x + 6x
5 = 7x
5/7 = x
