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dexar [7]
2 years ago
13

Doris is playing a game. She rolls three six-sided number cubes to tell her how many squares to move. If two number cubes show 4

and 3, how many different possible numbers of squares may she move on her turn?
Mathematics
1 answer:
koban [17]2 years ago
6 0

Answer:

6 possible values of squares that she can move.

Step-by-step explanation:

In these events, as given

Doris

- rolls 3 standard dice(s) (or is it die, dies?))

- two of them land on 4 and 3

-Find how many possible squares can she move

So, it is already known that Doris has to move 7 squares (because 3 + 4 = 7), yet she has another 6 sets of possibilities because a dice has 6 facets.

Hence she has 6 different possible numbers of squares she can move.

The possibilities are:

-8 squares (if she rolls a 1)

-9 squares (if she rolls a 2)

-10 squares (if she rolls a 3)

-11 squares (if she rolls a 4)

-12 squares (if she rolls a 5)

-13 squares (if she rolls a 6)

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Answer:

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Also, $ \textbf{x}^{\textbf{a}}. \textbf{x}^{\textbf{a}}  \textbf{=} \textbf{x}^{\textbf{a + a}} \textbf{=} \textbf{x}^{\textbf{2a}}  $

Using the above two results, we can say that:

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Step-by-step explanation:

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Step-by-step explanation:

Hey there!

Given expression is;

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