After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
Step-by-step explanation:
You can find the amount of students each vehicle can carry by representing the two scenarios in equations.
You are trying to find how many students will fit in each bus or van, so the two variables used will be "b" to represent how many students can fit in a bus and "v" to represent how many students can fit in a van.
High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.
High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.
Now, represent these in equations:

We can use substitution to solve this system:
can be rewritten as
after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":

After solving for b, you can then substitute the new value of b into the other equation to find the value of v:

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
The answer is 2 x10 = 20
To the power of b which is 15
The first discounted price is given through the equation,
discounted price = ($3.45)(1 - 0.20) = $2.76
Then, due to the privilege of being a Coles-Myer discount card holder, another 7.5% discount is given. Such that the final price would be,
final price = ($2.76)(1 - 0.075) = $2.553
The total amount saved up is equal to,
$3.45 - $2.553 = $0.897
The probability that the bulb is good is 12/15.
Since we have taken 1 item out the remaining total is now 14, so the probability of getting a defective bulb is now 3/14.
Now you multiply the probabilities together to get (12/15)(3/14)=(4/5)(3/14)=12/70=6/35
Answer:
D
Step-by-step explanation:
gegehehehjwjwjwjwwk