Solve ((9-2)^2)^3/(4+3)^5
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Answer:
The value of a will be
Step-by-step explanation:
Start by graphing the parabola and the three points of the triangle. These points are at intersections of y=a(x-1)(x-4) and the axes
so the y = 0 points are (1,0) and (4,0).
The x = 0 intersection is when y=a(-1)(-4) or (0,4a)
The base and height of this triangle are
The base would be the distance between the y=0 intersections and the height would be the y value of the other vertex.
Hence, base=3 units and height = 4a units. Thus, area can be calculated as
∵ the parabola opens downward therefore a will be negative.
hence,
The function f(x) is less than 0 at x < -1.8
<h3>How to analyze the graph?</h3>The missing graph is added as an attachment
The interval where f(x) < 0 are the intervals where the y value of the function is less than 0.
This in other words, represent the negative y-axis
From the attached graph, the function f(x) is less than 0 at x < -1.8.
This extends till x = infinity
Hence, the function f(x) is less than 0 at x < -1.8
Read more about function interval at:
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