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3 years ago

What is the nth term of the arithmetic sequence 7,5,3,1?

Mathematics

1 answer:

Minchanka [31]3 years ago

3 0

Answer:

tn = 7 + (n - 1)*(-2) or

tn = 9 - 2n

Step-by-step explanation:

You are (beginning with 7) subtracting 2 from the term to the left.

a = 7

d = -2

tn = a1 + (n - 1)*d

tn = 7 + (n - 1)*(-2)

Try this out on n = 4

t4 = 7 + (4 - 1)*-2

t4 = 7 + (3) (-2)

t4 = 7 - 6

t4 = 1 just as it says.

More generally

tn = 7 + (n - 1)*-2

tn = 7 + (-2n) + 2

tn = 9 - 2n

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Find the slope intercept form of slope-2 which passes through (-5,1)

dusya [7]

Answer:

$y=2x+11$

Step-by-step explanation:

So we know that the slope is 2 and the lines passes through the point (-5,1).

We can use the point-slope form. The point-slope form is:

$y-y_1=m(x-x_1)$

Where m is the slope and (x₁, y₁) is a point.

So, let's substitute 2 for m and (-5,1) for (x₁, y₁), respectively. Therefore:

$y-(1)=2(x-(-5))$

Simplify:

$y-1=2(x+5)$

Distribute the 2:

$y-1=2x+10$

Add 1 to both sides:

$y=2x+11$

So, the equation of our line is:

$y=2x+11$

6 0

2 years ago

A media company wants to track the results of his new marketing plan so the video production manager recorded the number of use

konstantin123 [22]

Answer:

$f(x)=5120(5)^{x}$

Step-by-step explanation:

From the image, f(x) and x are rlated by

$f(x)=a( {b})^{x}$

where b is the common ratio

We first find the value for b

$\frac{6400}{5120}= 5$

$\frac{8000}{6400}= 5$

$\frac{10000}{8000} = 5$

$\frac{12500}{10000} = 5$

$\frac{15625}{12500}=5$

so we can say the common ratio, b=5

we put in any value of f(x) and the corresponding value for x to find a value

Let put x=0 and f(x)=5120

This implies that

$5120 = a(5)^{0}$

but

$5^{0} = 1$

Hence a=5120

Thus the equation which model the relationship between the weeks and the viewers is

$f(x)=5120(5)^{x}$

6 0

2 years ago

A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and

gayaneshka [121]

Answer:

$(832.156, \ 847.844)$

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, $\overline x = 840$

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}$

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

$E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

$(840-7.844 , \ 840+7.844)$

$(832.156, \ 847.844)$

4 0

2 years ago

Ahh i hate math fr someone help

Dmitry_Shevchenko [17]

I think C but probably try to find something to back it up
All you gotta do is divide the pound by the cost

6 0

2 years ago

Help Me On One Of These Please!

gayaneshka [121]

We need more information on the stuff before we can answer it

8 0

2 years ago