What is the nth term of the arithmetic sequence 7,5,3,1?
1 answer:
Answer:
tn = 7 + (n - 1)*(-2) or
tn = 9 - 2n
Step-by-step explanation:
You are (beginning with 7) subtracting 2 from the term to the left.
a = 7
d = -2
tn = a1 + (n - 1)*d
tn = 7 + (n - 1)*(-2)
Try this out on n = 4
t4 = 7 + (4 - 1)*-2
t4 = 7 + (3) (-2)
t4 = 7 - 6
t4 = 1 just as it says.
More generally
tn = 7 + (n - 1)*-2
tn = 7 + (-2n) + 2
tn = 9 - 2n
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