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Otrada [13]
3 years ago
15

Rectangle MPAT has vertices M(1, 2) , P(1, 3) , A(3, 3) , and T(3, 2) . ​ Rectangle MPAT ​ was translated 1 unit right and 2 uni

ts up to produce rectangle M'P'A'T' .
Which coordinates describe the vertices of the image?


M'(3, 3), P'(3, 4), A'(5, 4) , and T'(5, 5)

M'(2, 2), P'(2, 3), A'(4, 3) , and T'(4, 2)

M'(2, 4) , P'(2, 5) , A'(4, 5) , and T'(4, 4)

M'(1, 4), P'(1, 5), A'(3, 5) , and T'(3, 4)
Mathematics
1 answer:
irakobra [83]3 years ago
4 0
M(1,2)
P(1,3)
A(3,3)
T(3,2)

Translated 1 unit right and 2 units up.
Simply add 1 to the x coordinate and 2 to the y coordinate.

M (1+1; 2+2) (2,4)
P(1+1 ; 3+2) (2,5)
A(3+1 ; 3+2) (4,5)
T(3+1 ; 2+2) (4,4)

My answer is: <span>M'(2, 4) , P'(2, 5) , A'(4, 5) , and T'(4, 4)</span>
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Is 1563/25 a rational number
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3 years ago
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

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Answer:

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Step-by-step explanation:

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