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Lina20 [59]
3 years ago
6

Miley went to the store with a $10 bill. She went to get 8 jumbo dill pickles for her family. If she spent the whole $10, what w

as the cost of each jumbo dill pickle?
Mathematics
2 answers:
vagabundo [1.1K]3 years ago
6 0
The answer is $1.25 because 10 divided by 8 is 1.25
Vadim26 [7]3 years ago
3 0

answer is 1.25

because 10 divided by 8 equals 1.25

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Find the volume in cubic meter (C.U.M) of each of the cuboid whose dimensions are :
Leno4ka [110]

The volume in cubic meter of the cuboid with the dimensions length = 12 m , breadth = 10m, height = 4.5 m is 540 m³

<h3 />

<h3>Volume of a cuboid:</h3>
  • v = lwh

where

l =- length

w = width

h = height

Therefore,

l = 12 m

w = 10 m

h = 4.5

v = 12 × 10 × 4.5

v = 120 × 4.5

v = 540 m³

learn more on cuboid here: brainly.com/question/14297267?referrer=searchResults

7 0
2 years ago
Read 2 more answers
a store is selling uniform shirts for 18.95 each. if samuel has a coupon for 1/4 off the price, how much would he pay for the sh
balandron [24]
First take the original price and multiple by 1/4 or .25. You should get 4.73 then you subtract that from 18.95 and your answer is 14.22
5 0
3 years ago
Pls pls help i realy need help
lisov135 [29]

Answer:

a <= 3

Step-by-step explanation:

4 0
3 years ago
In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x
KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at  y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))  y=\frac{8}{2}=4

6 0
3 years ago
If ON= 5x - 7, LM = 4x+ 4, NM = x -7, and OL =3y-4, find the values of c and y for which LMNO MUST BE a parallelogram.
Sholpan [36]

Answer:

x=11, y=8/3

Step-by-step explanation:

Consider quadrilateral LMNO. If this quadrilateral MUST BE a parallelogram, then

LM=NO

and

LO=MN

Thus,

\left\{\begin{array}{l}4x+4=5x-7\\ \\x-7=3y-4\end{array}\right.

Solve this system of two equations. From the first equation:

4x-5x=-7-4\\ \\-x=-11\\ \\x=11

Substitute it into the second equation:

11-7=3y-4\\ \\3y-4=4\\ \\3y=4+4\\ \\3y=8\\ \\y=\dfrac{8}{3}

4 0
3 years ago
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