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noname [10]
3 years ago
12

The "feasible region" has vertices (4,5), (4,6), (7,4), and (3,6). If the "objective function" that you are trying to minimize i

s C = 4x + 2y, what is the minimum value? Write the minimum value, not the point.
Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Answer:

The minimum value is 24

Step-by-step explanation:

we know that

The "feasible region" has vertices (4,5), (4,6), (7,4),(3,6)

The objective function is C=4x+2y

To determine the minimum value of the objective function, substitute the value of x and the value of y of each vertex in the objective function and then compare the values

1) For (4,5)

x=4,y=5

C=4(4)+2(5)=26

2) For (4,6)

x=4,y=6

C=4(4)+2(6)=28

3) For (7,4)

x=7,y=4

C=4(7)+2(4)=36

4) For (3,6)

x=3,y=6

C=4(3)+2(6)=24

therefore

The minimum value is 24

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Sholpan [36]

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A double cheeseburger has 540 calories, a milk shake has 490 calories and a serving of fries has 380 calories. If you burn 130 c
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2 years ago
The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu
Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

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- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

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- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

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