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GarryVolchara [31]
3 years ago
9

V+6=92 solve for v

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Answer:

x=86

Step-by-step explanation:

inysia [295]3 years ago
3 0

Answer:

v = 86

Step-by-step explanation:

v + 6 = 92

v + 6 = 92

   -6      -6

v = 86

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(+5)-(-3)=<br> (Integers)
saul85 [17]

Answer:

8

Step-by-step explanation:

it is positive 8 because the negative outside the parenthesis cancels out the -3 making it positive now give me brainliest

5 0
3 years ago
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Method for converting an angle in radians to degrees
vladimir1956 [14]

Answer:

Step-by-step explanation:

To solve for degrees: (180°/π) * radians

To solve for radians: (π/180°) * degrees

3 0
3 years ago
Let's solve the equation for x! 3x-3=180 *
Trava [24]
I think this is the answer

3 0
3 years ago
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What is the area of a sector with a central angle of (2pi/3) radians and a diameter of 12 in?
Stels [109]

Answer:

The area of the sector is 37.68\ in^{2}

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

we have

r=12/2=6\ in ----> the radius is half the diameter

substitute

A=(3.14)(6)^{2}

A=113.04\ in^{2}

step 2

Find the area of a sector with a central angle of (2pi/3)

Remember that

The area of 113.04\ in^{2} subtends a central angle of 2\pi \ radians

so

by proportion

Let

x----> the area of the sector

\frac{2\pi}{113.04}=\frac{(2\pi/3)}{x}\\ \\x=113.04*(2\pi/3)/(2\pi)\\ \\x=37.68\ in^{2}

8 0
3 years ago
QUESTION TWO Determine whether or not a constant function can be
Sveta_85 [38]
<h3>Answers:</h3>
  • (a) It is <u>never</u> one-to-one
  • (b) It is <u>never</u> onto

=========================================================

Explanation:

The graph of any constant function is a horizontal flat line. The output is the same regardless of whatever input you select. Recall that a one-to-one function must pass the horizontal line test. Horizontal lines themselves fail this test. So this is sufficient to show we don't have a one-to-one function here.

Put another way: Let f(x) be a constant function. Let's say its output is 5. So f(x) = 5 no matter what you pick for x. We can then show that f(a) = f(b) = 5 where a,b are different values. This criteria is enough to show that f(x) is not one-to-one. A one-to-one function must have f(a) = f(b) lead directly to a = b. We cannot have a,b as different values.

----------------------------

The term "onto" in math, specifically when it concerns functions, refers to the idea of the entire range being accessible. If the range is the set of all real numbers, then we consider the function be onto. There's a bit more nuance, but this is the general idea.

With constant functions, we can only reach one output value (in that example above, it was the output 5). We fall very short of the goal of reaching all real numbers in the range. Therefore, this constant function and any constant function can never be onto.

4 0
3 years ago
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