Question

A rectangular pool is surrounded by a walk 22 meters wide. the pool is 33 meters longer than its width. if the total area of the pool and walk is 268268 square meters more than the area of the​ pool, find the dimensions of the pool.

Answer 1

Let w be the width of the pool. Then its' length is w+3. Adding a 2 meter walk around the pool makes the total width w+4; and it's length w+7. So:
(w+4)(w+7)-w(w+3)=268
w^2+11w+28-w^2-3w-268=0
8w=240
w=30
The pool is 30'x33'
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