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AleksandrR [38]

3 years ago

11

If the diameter of a circle is 7/2, what is the radius, circumference in terms of pi and what is the approximate circumference?

Thank you so much to whoever answers this!!

2 answers:

ira [324]3 years ago

5 0

ITS 1.79 i think im not sure sorry if im wrong hope this helps :) :D

Nezavi [6.7K]3 years ago

4 0

The radius is 1.75 and the approximate circumference is 10.5 the pi circumference is 5.495 pi

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AnnyKZ [126]

Answer:

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(11/x^2-25)+(4/x+5)= 3/x-5

Ierofanga [76]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
\cfrac{11}{x^2-25}+\cfrac{4}{x+5}=\cfrac{3}{x-5}\implies \cfrac{11}{x^2-5^2}+\cfrac{4}{x+5}=\cfrac{3}{x-5}$

$\bf \cfrac{11}{(x-5)(x+5)}+\cfrac{4}{x+5}=\cfrac{3}{x-5}\impliedby 
\begin{array}{llll}
\textit{notice, LCD is }(x-5)(x+5)\\
\textit{so let's multiply all by it}\\
\textit{to toss the denominators}
\end{array}$

$\bf (x-5)(x+5)\left( \cfrac{11}{(x-5)(x+5)}+\cfrac{4}{x+5} \right)=(x-5)(x+5)\left( \cfrac{3}{x-5} \right)
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8 0

3 years ago

In circle S with mZRST = 86 and RS = 4 units find area of sector RST. Round to

Andru [333]

Answer:

$Area = 12.00$

Step-by-step explanation:

Given

$\theta = m\angle RST = 86^o$

$r = RS = 4$

Required

Area of RST

The sector area is calculated using:

$Area = \frac{\theta}{360} * \pi r^2$

So, we have:

$Area = \frac{86}{360} * 3.14 *4^2$

$Area = \frac{86* 3.14 *4^2}{360}$

$Area = \frac{4320.64}{360}$

$Area = 12.00$ ------------ approximated

8 0

3 years ago