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Usimov [2.4K]
3 years ago
6

Use factoring and the zero-product property to solve the following problems.

Mathematics
2 answers:
NemiM [27]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

Divide through by 2

2a² - 5a + 3 = 0

To factor the quadratic

Consider the factors of the product of the coefficient of the a² term and the constant term which sum to give the coefficient of the x- term

product = 2 × 3 = 6 and sum = - 5

The factors are - 2 and - 3

Use the factors to split the a- term

2a² - 2a - 3a + 3 = 0 ( factor the first/second and third/fourth terms )

2a(a - 1) - 3(a - 1) = 0 ← factor out (a - 1)

(a - 1)(2a - 3) = 0

Equate each factor to zero and solve for a

a - 1 = 0 ⇒ a = 1

2a - 3 = 0 ⇒ 2a = 3 ⇒ a = \frac{3}{2}

zhuklara [117]3 years ago
3 0

Answer:

a = 3/2 or 1

Step-by-step explanation:

4a²-10a+6=0

(Divide by 2)

2a²-5a+3=0

(Now factorise)

(2a-3)(a-1)

a = 3/2 or 1

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Step-by-step explanation:

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3 years ago
If y=mx, and y is 12 when x is 4, then what is the constant of proportionality in this equation?A. 1/3B. 3C. 8D. 16
Anna007 [38]
\begin{gathered} y=mx\text{  when  x=4 and y=12} \\ 12=m(4) \\ 4m\text{ =12} \\ m=\frac{12}{4}=3 \end{gathered}

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5 0
1 year ago
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cestrela7 [59]
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first \ term = 3t
The degree of the second term is... 2
second \ term = t^2
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third \ term = t^4

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c) The degree of the polynomial is... 4
6 0
3 years ago
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