Use factoring and the zero-product property to solve the following problems.
2 answers:
Answer:
see explanation
Step-by-step explanation:
Divide through by 2
2a² - 5a + 3 = 0
To factor the quadratic
Consider the factors of the product of the coefficient of the a² term and the constant term which sum to give the coefficient of the x- term
product = 2 × 3 = 6 and sum = - 5
The factors are - 2 and - 3
Use the factors to split the a- term
2a² - 2a - 3a + 3 = 0 ( factor the first/second and third/fourth terms )
2a(a - 1) - 3(a - 1) = 0 ← factor out (a - 1)
(a - 1)(2a - 3) = 0
Equate each factor to zero and solve for a
a - 1 = 0 ⇒ a = 1
2a - 3 = 0 ⇒ 2a = 3 ⇒ a =
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Answer:
The square of a monomial is
Step-by-step explanation:
Consider the provided monomial.
We need to Write the expression as a square of a monomial.
The above expression can be written as:
Hence, the square of a monomial is