Question

Use factoring and the zero-product property to solve the following problems.

Answer 1

Answer:

see explanation

Step-by-step explanation:

Divide through by 2

2a² - 5a + 3 = 0

To factor the quadratic

Consider the factors of the product of the coefficient of the a² term and the constant term which sum to give the coefficient of the x- term

product = 2 × 3 = 6 and sum = - 5

The factors are - 2 and - 3

Use the factors to split the a- term

2a² - 2a - 3a + 3 = 0 ( factor the first/second and third/fourth terms )

2a(a - 1) - 3(a - 1) = 0 ← factor out (a - 1)

(a - 1)(2a - 3) = 0

Equate each factor to zero and solve for a

a - 1 = 0 ⇒ a = 1

2a - 3 = 0 ⇒ 2a = 3 ⇒ a = $\frac{3}{2}$

Answer 2

Answer:

a = 3/2 or 1

Step-by-step explanation:

4a²-10a+6=0

(Divide by 2)

2a²-5a+3=0

(Now factorise)

(2a-3)(a-1)

a = 3/2 or 1