Question

The playing field for a particular sport is a rectangle whose length is 4 feet more than twice the width. The perimeter of the playing field is 200 feet. Find the dimensions of the playing field.

Answer 1

Answer:

The length and width of the field are 68ft and 32ft respectively

Step-by-step explanation:

Given:

Rectangular Playing Field

Perimeter. P = 200 ft

Required

The dimension of the field (Length and Width)

Let L and W represent the length and the width of the field.

From the question, L is 4 more than twice of W.

This means

L = 4 + 2W

Provided that the playing field is rectangular in shape;

We need to make use of the formula of perimeter of a rectangle.

P = 2(L + W)

Substitute 200 for P

200 = 2(L + W)

Divide through by 2

$\frac{200}{2} = \frac{2(L + W)}{2}$

100 = L + W

Recall that L = 4 + 2W

Substitute 4 + 2W for L

100 = L + W becomes

100 = 4 + 2W + W

100 = 4 + 3W

Subtract 4 form both sides

100 - 4 = 4 + 3W - 4

96 = 3W

Divide both sided by 3

$\frac{96}{3} = \frac{3W}{3}$

32 = W

W = 32

Recall that L = 4 + 2W

Substitute 32 for W

L = 4 + 2(32)

L = 4 + 64

L = 68

Hence the length and width of the field are 68ft anf 32ft respectively