QUESTION 1
The given binomial is;

First terms are multiplied: 
Outside terms are multiplied: 
Inside terms are multiplied: 
Last terms are Multiplied: 
This gives us;


QUESTION 2
We want to factor

The HCF is 
We factor to get;

QUESTION 3;

Split the middle term;

Factor




The solutions are;
and 
These are the x-intercepts of the graph of the function

Answer:
308 would be the number you are looking for.
Step-by-step explanation:
Answer:
Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
Step-by-step explanation:
Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:
6000 + 3B + B = 24000
3B + B = 24000 - 6000
4B = 18000
B = 18000/4
B = 4500
S = 6000 + 3x4500
S = 6000 + 13500
S = 19500
Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
I believe it would be (4,5)