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Ivahew [28]
2 years ago
7

What is the value of f(g(3))

Mathematics
2 answers:
denpristay [2]2 years ago
7 0

Answer:

A

Step-by-step explanation:

f(g(3)= f(g(x=3)) = f(\frac{3+1}{3-1}) = f(4/2) = f(2) = f(x=2) = 3*2-7 = 6-7 = -1

Scilla [17]2 years ago
4 0

Answer:

Step-by-step explanation:

A . It is the correct answer

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What is the difference?<br><br> 10.22 – 3.651
zysi [14]

Answer:

6.569

Step-by-step explanation:

Difference is subtraction.

10.22-3.651=6.569

7 0
3 years ago
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Can you help me please​
kotegsom [21]

Answer:

3

Step-by-step explanation:

3 0
2 years ago
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What mathematical term describes both 5.3 and 8.2 in the expression 5.3x-8.2y+11.1?
kiruha [24]

Answer:

Step-by-step explanation:

Coefficients

5 0
3 years ago
What is the distribution property of 4 times 37
hjlf

Answer:

  4(30 +7) = 120 +28 = 148

Step-by-step explanation:

When applying the distributive property to integers, we usually break them apart according to place value. That is not the only way it can be done.

  4×37 = 4(30 +7) = 4·30 +4·7 = 120 +28 = 148

___

You can also break apart 37 other ways:

  4×37 = 4(35 +2) = 4·35 +4·2 = 140 +8 = 148

  4×37 = 4(40 -3) = 4·40 -4·3 = 160 -12 = 148

Or, you can break apart 4:

  37×4 = 37(2 +2) = 37·2 +37·2 = 74 +74 = 148

_____

The distributive property is usually written in generic form as ...

  a(b+c) = ab +ac

Then you may want to stop after the first couple of steps:

  4(30 +7) = 4·30 +4·7

We can't tell if you're suppose to evaluate the expression or not. Check your reference materials for an example of this kind of problem.

7 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
3 years ago
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