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laila [671]
3 years ago
5

If it takes 125 joules to heat a piece of gold weighing 35 g from 18.0 °C to 43.0 °C, what is the specific heat of the gold?

Mathematics
1 answer:
kari74 [83]3 years ago
3 0
The specific heat of the gold is 1.67 (=125/(3*(43-18)) joule/ gram oC based on its heat energy, change in temperature and mass. This problem can be solved using the heat energy formula which stated as Q=c*m*(deltaT). In this formula, Q is the heat energy, c is the specific heat, m is the object's mass, and deltaT is the change in the temperature of the reaction<span>.</span>
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You have the correct answer. It is choice B) -1/4

=======================================================

Explanation:

This is because we're adding -1/4 to each term to get the next one. In other words, we're subtracting 1/4 from each term to get the next one.

  • term2 = term1+(d) = 1/2 + (-1/4) = 1/2 - 1/4 = 2/4 - 1/4 = 1/4
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and so on.

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To find the common difference, all we have to do is subtract any term from its previous one.

For example:

d = (term2) - (term1)

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d = (1/4) - (2/4)

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The order of subtraction matters, so we cannot say d = term1-term2.

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3 years ago
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