Answer:
36°
hope it helps and your day will be full of happiness
Answer:
a)120
b)6.67%
Step-by-step explanation:
Given:
No. of digits given= 6
Digits given= 1,2,3,5,8,9
Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be
6P3= 6!/3!
= 6*5*4*3*2*1/3*2*1
=6*5*4
=120
Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:
As the first and last digits can only be even
then the form of number can be
a)2n8 or
b)8n2
where n can be 1,3,5 or 9
4*2=8
so there can be 8 three-digit numbers with both the first digit and the last digit even numbers
And probability = 8/120
= 0.0667
=6.67%
The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !
The correct answer is: 11
Here’s how you solve it!
You can remove the 0 since when you add or subtract 0 it stays the same.
Then you would want to look at the first set of parentheses (-20)
Since it is -(-20) this changes the sign to a positive +20
9-5+20+(-13)
Now since the + is in front of the (-13) it remains the same.
Now you are left with this:
9-5+20-13
9-5=4
4+20=24
24-13=11
Then you are left with your answer: 11
Hope this helps! :3
7 tenths, 7/10. or 70 percent.
we know that
<u>in the triangle PQR</u>
m∠PQR+m∠QPR+m∠QRP=180°------> the sum of the internal angles of a triangle is equal to 180 degrees
(m∠PQR+m∠QRP)+74°=180°-------> (m∠PQR+m∠QRP)=106°
we know that
If QS and SR are angle bisectors
then
<u>In the triangle QSR</u>
m∠SQR+m∠QSR+m∠QRS=180°-------> equation 1
and
(m∠SQR+m∠QRS)=106°/2--------> (m∠SQR+m∠QRS)=53°
substitute the value of (m∠SQR+m∠QRS)=53° in the equation 1
53°+m∠QSR=180°
m∠QSR=180°-53°-------->m∠QSR= 27°
therefore
<u>the answer is</u>
The measure of angle QSR is 27 degrees
