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3 years ago

Please help me thank you

Mathematics

1 answer:

aivan3 [116]3 years ago

5 0

Answer:

Q1: -2

Q2: 13

Q3: 15

Q4: -12

Q5: 7

Q6: -4

Q7: 12p + 3

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Find the slant height l of the cone given the surface area S.

Oduvanchick [21]

9514 1404 393

Answer:

15 cm

Step-by-step explanation:

The formula for the surface area of the cone is ...

A = πr² +πrL = πr(r +L)

The radius of this cone is half its diameter so is (12 cm)/2 = 6 cm. Then the slant height L can be found from ...

126π cm² = π(6 cm)(6 cm +L)

21 cm = 6 cm +L . . . . . . . . . . . . . . divide by 6π cm

15 cm = L . . . . . . . . . . . . . . . . subtract 6 cm

The slant height is 15 centimeters.

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2 years ago

What is -3 1/6+5 3/5<br> help me please and thank you

balandron [24]

The answer should be 2 13/30.

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3 years ago

Explain how to verify that 3(2x + 5) = 9 + 3x and x = –2 are equivalent equations.

aniked [119]

3 times (2x + 5) is 6x + 15.

6x + 15 = 9 + 3x.

Group by like terms. 6 = -3x

Divide to get x by itself. 6/-3 = -2

Thus -2 = x

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3 years ago

My last question someone help pls

lara [203]

Answer:

Step-by-step explanation:

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2 years ago

Simplify the following Questions. (IMPORTANT NOTE!!! #'s 2 AND 7 MUST BE IN SCIENTIFIC NOTATION!!!!!) 1.) (x)²(2xy³)^5 2.) (4x10

poizon [28]

Answer:

Step-by-step explanation:

Hint :

$(a*b)^{m}= a^{m}b^{m}\\\\\\(a^{m})^{n}=a^{mn}\\\\\\a^{m}*a^{n}=a^{m+n}\\$

$1)x^{2}(2xy^{3})^{5}=x^{2}*2^{5}*x^{5}*(y^{3})^{5}\\\\\\=x^{2}*2^{5}*x^{5}*y^{3*5}\\\\=x^{2}*2^{5}*x^{5}*y^{15}\\\\=2^{5}*x^{2+5}*y^{15}\\\\=2^{5}x^{7}y^{15}$

$2) (4x10^{8})^{2}=4^{2}*x^{2}*(10^{8})^{2}\\\\=16*x^{2}*10^{8*2}\\\\=1.6*10*x^{2}*10^{16}\\\\=1.6x^{2}*10^{16+1}\\\\=1.6x^{2}10^{17}$

$3)(-h^{4})^{5}=(-h)^{4*5}=-h^{20}\\\\\4)(3xy^{3})^{2}(xy)^{6}=3^{2}x^{2}(y^{3})^{2}x^{6}y^{6}\\\\=9x^{2}y^{3*2}x^{6}y^{6}\\\\\\=9x^{2}y^{6}x^{6}y^{6}\\\\=9x^{2+6}y^{6+6}\\\\=9x^{8}y{12}\\\\\\$

$5) (p^{9})^{-2}=p^{9*-2}=p^{-18}\\\\\\6)(5k^{2})^{3}=5^{3}(k^{2})^{3}=625k^{6}\\\\7)(7x10^{5})^{2}=7^{2}x^{2}(10^{5})^{2}\\\\=49x^{2}10^{5*2}\\\\=4.9*10^{1}x^{2}10^{10}\\\\=4.9x^{2}10^{10+1}\\\\=4.9x^{2}10^{11}$

$8)x^{3}(-x^{3}y)^{2}=x^{3}*(-x^3})^{2}y^{2}\\\\\\=x^{3}*(-1)^{2}*x^{2*3}y^{2}\\\\=x^{3}*1*x^{6}y^{2}=x^{3+6}y^{2}\\\\=x^{9}y^{2}\\\\\\9)w^{5}(w^{2})^{-4}=w^{5}w^{2*-4}\\\\=w^{5}w^{-8}\\\\=w^{5-8}=w^{-3}\\\\=\frac{1}{w^{3}}\\\\\\10) (2x^{5})^{4}=2^{4}x^{5*4}\\\\=2^{4}x^{20}\\\\=16x^{20}$

5 0

3 years ago

Please help me thank you​

Please help me thank you