Given:
The vertices of a triangle ABC are A(-3,-4), B(16,-2) and C(13,-10).
To show:
That the triangle ABC is a right angled triangle.
Solution:
Distance formula:
The vertices of a triangle ABC are A(-3,-4), B(16,-2) and C(13,-10).
Using the distance formula, we get
Similarly,
And,
Now, add the square of two smaller sides.
Since the sum of the square of two smaller sides is equal to the square of the largest side, therefore the given triangle is a right angle triangle by using Pythagoras theorem.
Hence proved.
Answer:
-5/-2 or 2.5
Step-by-step explanation:
Because you gave two points that I'm guessing are from the graph I think that's the answer. Because when you use the slope formula y2-y1 over x2 - x1 you get -5/-2 or you either get 2.5 meaning that is the slope specifically saying the rate of change. You get 2.5 when you divide -5/-2 incase you need a decimal or want to simplfy it.
Answer:
-7
Step-by-step explanation:
Coordinates are listed as (x,y) so x = -5 and y = .5
If you substitute the numbers in place of the letters, you get:
(-5) - 4(.5) = -7
-5 - 2 = -7
-7 = -7
Marking as Brainliest is much appreciated.
2x^3 + x^2 - 4x - (9x^3 - 3x^2) =
2x^3 + x^2 - 4x - 9x^3 + 3x^2 =
-7x^3 + 4x^2 - 4x <===
F(6)=2
That is because the 6 in the brackets means x
If f(x) means f(6) x=6
And if you look at the graph where the 6 on the x axis is and look where the graph meets the value of 6 it is on the value of 2 on the y axis
